Nettet求数学高手解答几道不定积分的题.1、 ∫tan^4dx；2、 ∫sinxsin2xsin3xdx；3、∫（sinxcosx)/(1+sin^4x)dx. NettetTurunan dari y=(1-cosx) sin x adalah A. Cos x + 1/2 cos 2x B. Cos x + cos 2x C. Sin x - 1/2 cos 2x D. Sin x - cos 2x E. Cos x - cos 2x Cara dan jawaban terlampir

∫ _{pi/4}^frac{pi{3}}cos(4x)/cos(2x)-sin(2x) wrt x= ਨੂੰ ਹੱਲ ਕਰੋ ...

NettetOldja meg matematikai problémáit ingyenes Math Solver alkalmazásunkkal, amely részletes megoldást is ad, lépésről lépésre. A Math Solver támogatja az alapszintű matematika, algebra, trigonometria, számtan és más feladatokat. Nettet2.计算下列定积分0( ∫_1^2(1/x+2)dx ( ∫_(-π)^π(sinx-cosx)dx(sin x-cos x)dx;4cos2xdx.0 maltreatment lawyer

sin^4x+cos^4x - Wolfram Alpha

NettetSolution Let I = ∫ 1 cos 4 x + sin 4 x d x Divide numerator and denominator by cos 4 x, we get: ∫ sec 4 x 1 + tan 4 x dx ∫ sec 2 x ( sec 2 x) 1 + tan 4 x dx ∫ sec 2 x ( 1 + tan 2 x) 1 + tan 4 x dx Putting tan x = t, Sec 2 x dx = dt I = ∫ 1 + t 2 1 + t 4 d t Dividing the numerator and denominator by t 2, we get: I = ∫ 1 + t 1 2 t 1 2 + t 2 NettetTherefore, multiplying by 4 5 and adding in the constant of integration, we see that ∫ e 2 x sin 4 x d x = − 1 5 e 2 x cos 4 x + 1 10 e 2 x sin 4 x + C, which we can rewrite as ∫ e 2 x sin 4 x d x = 1 10 e 2 x ( − 2 cos 4 x + sin 4 x) + C. Share Cite Follow edited Jan 17, 2014 at 16:24 Cameron Buie 101k 9 93 215 answered Jan 17, 2014 at 14:47 Nettet7. mai 2015 · How do you prove #sin^4x-cos^4x=sin^2x-cos^2x#? Trigonometry Trigonometric Identities and Equations Proving Identities. 1 Answer maltreatment of prisoners rpc